Question

2-Methyl butane on reacting with bromine in presence of sunlight gives mainly :

• A. 1-Bromo-2-methyl butane
• B. 2-Bromo-2-methyl butane
• C. 2-Bromo-3-methyl butane
• D. 1-Bromo-3-methyl butane

Answer 1

The correct option is B 2-Bromo-2-methyl butane

$C{H}_{3}CH\left(C{H}_3\right)C{H}_{2}C{H}_3+B{r}_2\stackrel{sunlight}{⟶}{H}_{3}CC\left(Br\right)\left(C{H}_3\right)C{H}_{2}C{H}_3$

The reaction proceeds via the free radical mechanism.

Since the radical formed in this case is tertiary, as it is more stable than primary and secondary, 2-Bromo-2-methyl butane is formed.

Option B is correct.