2 – Methylbutane on reacting with bromine in the presence of sunlight gives mainly

1 – bromo – 2 – methyl butane

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2 – bromo – 2 methyl butane

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2 – bromo – 3 methyl butane

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1 – bromo – 3 methyl butane

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Solution

The correct option is B 2 – bromo – 2 methyl butane
$H_{3} C - C H (C H_{3}) - C H_{2} - C H_{3} B r_{2}, h v - --- \to C H_{3} - C (C H_{3}) (B r) - C H_{2} - C H_{3}$

This is because reactivity order of abstraction of H atom from alkanes is $3^{\circ}$ > $2^{\circ}$ > $1^{\circ}$

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B r_{2}

B r_{2}

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