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Question

2 molal solution of a weak acid HA has a freezing point of 3.885oC. The degree of dissociation of this acid isx×103.

The value of x (Round off to the Nearest Integer) is

[Given : molal depression constant of water = 1.85 K kgmol1]
Freezing point of pure water = 0oC

A
50.00
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B
50.0
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C
50
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Solution

HA H++A
1α α α
(α-degree of dissociation)
van't Hoff factor (i)=1+α
ΔTf=iKfm
m is molality
ΔTf is depression in freezing point
Kf is cryoscopic constant
i is van't Hoff factor
3.885=(1+α)×1.85×2
(1+α)=1.05
α=0.05=50×103
x=50

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