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Byju's Answer
Standard XII
Chemistry
Characteristics of Chemical Equilibrium
2 mole each o...
Question
2 mole each of
P
C
l
5
and
C
l
2
and 1 mole of
P
C
l
3
are taken in 5lt. flask at
27
o
C
. After following equilibrium is attained in gaseous phase,
P
C
l
5
⇌
P
C
l
3
+
C
l
2
,
P
C
l
5
is found to be 40% dissociated. Calculate equilibrium constant
K
c
.
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Solution
P
C
l
5
⇌
P
C
l
3
+
C
l
2
2
m
o
l
1
m
o
l
2
m
o
l
2
−
2
α
m
o
l
(
1
+
2
α
)
m
o
l
(
2
+
2
α
)
m
o
l
As degree of dissociation,
α
=
40
%
=
0.4
Volume
=
5
l
------ (given)
∴
[
P
C
l
5
]
=
2
(
1
−
α
)
V
=
2
(
1
−
0.4
)
5
=
0.24
M
[
P
C
l
3
]
=
1
+
2
α
V
=
1
+
2
×
0.4
5
=
0.36
M
[
C
l
2
]
=
2
+
2
×
0.4
5
=
0.56
M
Now
K
c
=
[
P
C
l
3
]
[
C
l
2
]
[
P
C
l
5
]
K
c
=
0.36
×
0.56
0.24
K
c
=
0.84
m
o
l
/
l
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1
Similar questions
Q.
Two moles of
P
C
l
5
were introduced in a
2
litre flask and heated at
600
K
to attain equilibrium.
P
C
l
5
was found to be
40
% dissociated into
P
C
l
3
,
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l
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.
Q.
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+
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l
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is
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o
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e
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Q.
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C
l
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P
C
l
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and
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The value of equilibrium constant is:
Q.
2
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