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Carnot Cycle

2 mole of ide...

Question

2 mole of ideal gas at $27^{o} C$ temperature is expanded reversibly from 2 litre to 20 litre. Find entropy change:
( $R = 2 c a l / m o l K$ )

A

92.1

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B

0

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C

4

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D

9.2

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Solution

The correct option is B 9.2
Given $n = 2; T = 300 K; V_{1} = 2 L; V_{2} = 20 L; R = 2 c a l / m o l K$

$△ S = \frac{q}{T} = \frac{- W}{T}$

$△ S = \frac{- (- 2.303 n R T l o g (V_{1} / V_{2}))}{T}$

$△ S = 2.303 \times 2 \times 2 \times l o g (20 / 2)$

$△ S = 9.212 C a l / K / m o l$

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