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Question

2 mole of zinc is dissolved in HCl at 25oC. The work done in open vessel is :

A
2.477 kJ
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B
4.955 kJ
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C
0.0489 kJ
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D
None
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Solution

The correct option is C 4.955 kJ

Given n=2; T=25oC=298K; R=8.314 J/mol.K

W is the work done.

W=PV

=nRT

W=2×8.314×298

=4.955 kJ

Hence,option B is correct.


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