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Uses of Alkaline Earth Metals

2 moles of ...

Question

$2$ moles of $50 %$ pure $C a (H C O_{3})_{2}$ on heating forms $1$ mole of $C O_{2}$ . Thus, percent yield of $C O_{2}$ is :
$C a (H C O_{3})_{2} Δ - \to C a O + H_{2} O + 2 C O_{2}$

50 %

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75 %

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80 %

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100 %

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Solution

The correct option is C $50 %$
Given the reaction:
$C a (H C O_{3})_{2} Δ - \to C a O + H_{2} O + 2 C O_{2}$
$2$ moles of $50 %$ pure $C a (H C O_{3})_{2}$ means one mole of $C a (H C O_{3})_{2}$ .
So, according to reaction, $2$ moles of $C O_{2}$ should form but, as only one mole formed.
Therefore, $%$ yield $= \frac{100}{2} = 50 %$ .

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