Question

$2$ moles of an ideal monoatomic gas is carried from a state $(P_0,V_0)$ to a state $(2P_0,2V_0)$ along a straight line path in a P-V diagram. The amount of heat absorbed by the gas in the process is given by

• A. $3P_0{V}_0$
• B. $\frac{9}{2}{P}_0{V}_0$
• C. $6P_0{V}_0$
• D. $\frac{3}{2}{P}_0{V}_0$

Answer 1

Answer: (C)

$6P_0{V}_0$

$V_0\Delta U=n{C}_v\Delta T=n\frac{3R}{2}(\frac{4P_0{V}_0}{nR}-\frac{P_0{V}_0}{nR})=\frac{9}{2}{P}_0{V}_0$
$w=(2P_0+P_0)\frac{V_0}{2}=\frac{3P_0{V}_0}{2},\Delta Q=W+\Delta U=6P_0{V}_0$