Question

2 moles of $H_{2}S{O}_4$ present in 1 kg of solution then calculate normality of $H_{2}S{O}_4$ solution if density of solution is 1.25 gm/ml.

Answer 1

Given, Density of solution=$1.25gm/mol$

We know,

$Molarity=\frac{Wt}{GMWt}\times \frac{1000}{Vinml}$

$=\frac{Wt}{Vinml}\times \frac{1000}{GMWt}$

$Molarity=d\times \frac{1000}{GMWt}$

$[\because d=\frac{Weight}{Volume}]$

$\therefore Molarity=1.25\times \frac{1000}{98}$

$[\because H_{2}S{O}_4=98g/mol]$

$\Rightarrow$Molarity of solution=$12.755M$

Now, we know Normality=$Molarity\times nfactor$

Here, $H_{2}S{O}_4$ is an acid & for an acid n factor is basicity

Basicity of $H_{2}S{O}_4=2$

$\Rightarrow$ Normality of solution=$12.755\times 2=25.51N$