Question

2 moles of $N_2$ are mixed with 6 moles of $H_2$ in a closed vessel of one litre capacity. If 50% $N_2$ is converted into $N{H}_3$ at equilibrium, the value of $K_c$ for the reaction, $N_2\left(g\right)+3H_2\left(g\right)\rightleftharpoons 2N{H}_3\left(g\right)$

• A. $4/27$
• B. $27/4$
• C. $1/27$
• D. $27$

Answer 1

Answer: (A)

$4/27$

$N_2+3H_2\rightleftharpoons 2N{H}_3$
Initial $2$ mol $6$ mole
At eqm $1$ mol $3$ mol $2$ mol
MOlar conc$132mol{L}^{-1}$
$K_c=\frac{(2{)}^2}{1\times (3{)}^2}=\frac{4}{27}$