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Question

2 moles of N2 are mixed with 6 moles of H2 in closed vessel of one litre capacity. If 50% N2 is converted into NH3 at equilibrium, the value of Kc for the reaction,
N2(g)+3H2(g)2NH3(g)

A
4/27
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B
27/4
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C
1/27
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D
27
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E
9
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Solution

The correct option is A 4/27

N2(g)+3H2(g)2NH3(g)

Since total volume is 1 L, the number of moles is equal to the molar concentration.

2 moles of N2 are mixed with 6 moles of H2 in closed vessel of one litre capacity.
If 50% N2 is converted into NH3 at equilibrium.

2×50100=1 mole of N2 will react with
3×1=3 moles of H2 to form 2×1=2 moles of NH3

21=1 mole of N2 and 63=3 moles of H2 will remain at equilibrium.

Kc=[NH3]2[N2][H2]3

Kc=221×33


Kc=427

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