2 moles of O2(g), 3 moles of H2(g), and 1 mole of He(g) are in a 600 ml container. Within container, total pressure is 760 torr. What is the partial pressure of O2?
A
253 torr
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B
127 torr
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C
760 torr
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D
380 torr
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E
507 torr
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Solution
The correct option is A 253 torr Mole fraction of O2=22+3+1=0.333 The partial pressure of O2 is obtained by multiplying total pressure with mole fraction. It is 760×0.333=253torr.