$2 n^{2} - 6 n + 32$

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Solution

$2 n^{2} - 6 n + 32 = 0$

$a = 2, b = - 6, c = 32$

$n = \frac{- (- 6) \pm \sqrt{{(- 6)}^{2} - 4 \cdot 2 \cdot 32}}{2 \cdot 2}$

$n = \frac{3}{2} \pm i \frac{\sqrt{55}}{2}$

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