2 numbers are less than 60 and 3 numbers are more than 60. The numbers which are less have a difference of 10 and 20, respectively, from 60.

The numbers which are more, have a difference of 10, 20 and 30, from 60. What is the average of these numbers (including 60)?

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Solution

The numbers less than 60 are 40 and 50.

The numbers greater than 60 are 70, 80, and 90.

Now, we have 6 numbers.

The average of these numbers inclusive of 60 = $\frac{40 + 50 + 60 + 70 + 80 + 90}{6}$ = $\frac{390}{6}$ = 65

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Following are the ages (in years) of 360 patients, getting medical treatment in a hospital:

Age (in years)	10 – 20	20 – 30	30 – 40	40 – 50	50 – 60	60 – 70
Number of patients	90	50	60	80	50	30

One of the patients is selected at random.
What is the probability that his age is
(i) 30 years or more but less than 40 years?
(ii) 50 years or more but less than 70 years?
(iii) 10 years or more but less than 40 years?
(iv) 10 years or more?
(v) less than 10 years?

Q. Following are the ages (in years) of 360 patients, getting medical treatment in a hospital:

Age (in years)	10−20	20−30	30−40	40−50	50−60	60−70
Number of patients	90	50	60	80	50	30

One of the patients is selected at random.
Find the probability that his age is
(i) 30 years or more but less than 40 years
(ii) 50 years or more but less than 70 years
(iii) less than 10 years
(iv) 10 years or more

Q. Calculate mode from the following data:

Wages (₹)	Number of Workers
Less than 10 Less than 20 Less than 30 Less than 40 Less than 50 Less than 60 Less than 70 Less than 80	15 35 60 84 96 127 198 250

Following are the ages (in years) of 360 patients, getting medical treatment in a hospital:

$\begin{matrix} Age & 10 - 20 & 20 - 30 & 30 - 40 & 40 - 50 & 50 - 60 & 60 - 70 (in years) Number of patients & 90 & 50 & 60 & 80 & 50 & 30 \end{matrix}$

One of the patients is selected at random.

What is the probability that his age is

(i) 30 years or more but less than 40 years?

(ii) 50 years or more but less than 70 years?

(iii) 10 years or more but less than 40 years?

(iv) 10 years or more?

(v) less than 10 years?

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2 numbers are less than 60 and 3 numbers are more than 60. The numbers which are less have a difference of 10 and 20, respectively, from 60. The numbers which are more, have a difference of 10, 20 and 30, from 60. What is the average of these numbers (including 60)?

The numbers less than 60 are 40 and 50. The numbers greater than 60 are 70, 80, and 90. Now, we have 6 numbers. The average of these numbers inclusive of 60 = 40+50+60+70+80+906 = 3906 = 65

2 numbers are less than 60 and 3 numbers are more than 60. The numbers which are less have a difference of 10 and 20, respectively, from 60.

The numbers which are more, have a difference of 10, 20 and 30, from 60. What is the average of these numbers (including 60)?

The numbers less than 60 are 40 and 50.

The numbers greater than 60 are 70, 80, and 90.

Now, we have 6 numbers.

The average of these numbers inclusive of 60 = $\frac{40 + 50 + 60 + 70 + 80 + 90}{6}$ = $\frac{390}{6}$ = 65