$2 sin 30 ˚ + 2 tan 45 ˚ - 3 cos 60 ˚ - 2 {cos}^{2} 30 ˚ =$

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0$
$2 sin 30 ˚ + 2 tan 45 ˚ - 3 cos 60 ˚ - 2 {cos}^{2} 30 ˚$
$= 2 \times \frac{1}{2} + 2 \times 1 - 3 \times \frac{1}{2} - 2 {(\frac{\sqrt{3}}{2})}^{2}$
$= 1 + 2 - \frac{3}{2} - \frac{3}{2}$
$= 0$

Suggest Corrections

Similar questions

Evaluate the following:
$2 s i n 30^{\circ} + 3 c o s 60^{\circ} - 3 t a n 45^{\circ}$

\frac{2 t a n 45^{\circ}}{1 + t a n^{2} 45^{\circ}}

$c o t^{2} 30^{\circ} - 2 c o s^{2} 30^{\circ} - \frac{3}{4} s e c^{2} 45^{\circ} + \frac{1}{4} c o s e c^{2} 30^{\circ}$

cos 60^{\circ} = 1 - 2 {sin}^{2} 30^{\circ} = 2 {cos}^{2} 30^{\circ} - 1

\frac{2 tan 45^{\circ}}{1 + {tan}^{2} 45^{\circ}}

Join BYJU'S Learning Program