$2 sin A sin B$ is equal to $cos (A + B) - cos (A - B)$

True

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False

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Solution

The correct option is B False

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Similar questions

Prove that cos(A-B)-cos(A+B)=2sinAsinB

x = sin (α - β) sin (γ - δ)

y = sin (β - γ) sin (α - δ)

z = sin (γ - α) sin (β - δ)

x + y + z = 0

2 sin A sin B = cos (A - B) + cos (A + B)

\frac{1 - cos A + cos B - cos (A + B)}{1 + cos A - cos B - cos (A + B)} =

\frac{cos (A - B)}{cos (A + B)} + \frac{cos (C + D)}{cos (C - D)} = 0 \Rightarrow tan A tan B tan C tan D

\frac{cos (A + B)}{cos (A - B)} + \frac{cos (C - D)}{cos (C + D)} = 0

cot A cot B cot C

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