Question

$2\sin x^0-1=0$ and $x^0$ is an acute angle. If $\cos x^0$ is $\frac{\sqrt{m}}{2}$, $m$ is

Answer 1

$2sin{x}^{\circ }-1=0$
$2sin{x}^{\circ }=1$
$sin{x}^{\circ }=\frac{1}{2}$
$sin{x}^{\circ }=sin{30}^{\circ }$
$x={30}^{\circ }$
Now, $cos{x}^{\circ }=cos{30}^{\circ }=\frac{\sqrt{3}}{2}$
$tan{x}^{\circ }=tan{30}^{\circ }=\frac{1}{\sqrt{3}}$