Question

$2\sin x^0-1=0$ and $x^0$ is an acute angle. If $\sin x^0$ is $\frac{1}{m}$, then $m$ is:

Answer 1

$2sin{x}^{\circ }-1=0$
$2sin{x}^{\circ }=1$
$sin{x}^{\circ }=\frac{1}{2}$