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Question

2. Solve 5 examples for each identity that you use for factorization
i)a2+b2 +2ab= (a+b)2
ii)a2+b2-2ab=(a-b)2
iii)a3+b3 = (a+b)(a2+b2-ab)

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Solution

Dear student
Take a=5 and b=2 (say)1) a+b2=a2+b2+2ab5+22=52+22+25272=25+4+2049=49 2)a-b2=a2+b2-2ab5-22=52+22-25232=25+4-209=93) a3+b3=a+ba2+b2-ab53+23=5+252+22-52125+8=7×19133=133Similarly you can take different values and prove the identities.Regards

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