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Polynomial

Question 2 2 ...

Question

Question 2
$2 \sqrt{2}$ is a polynomial of degree

A) 2
B) 0
C) 1
D) $\frac{1}{2}$

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Solution

The answer is B.
$2 \sqrt{2} = 2 \sqrt{2} x^{\circ}$ .
$2 \sqrt{2}$ is a polynomial of degree 0, because exponent of x is 0.

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Similar questions

Q. Question 2

2 \sqrt{2}

is a polynomial of degree

A) 2
B) 0
C) 1
D)

\frac{1}{2}

a^{2} + b^{2} + c^{2} = - 2

f (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 + a^{2} x & (1 + b^{2}) x & (1 + c^{2}) x (1 + a^{2}) x & 1 + b^{2} x & (1 + c^{2}) x (1 + a^{2}) x & (1 + b^{2}) x & 1 + c^{2} x \end{matrix} ∣ ∣ ∣ ∣ ∣

then f(x) is a polynomial of degree

\frac{x}{x - 1} + \frac{1}{x + 1} + \frac{2 x}{1 - x^{2}} .

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(a) $- 2$

(b) $0$

(c) $1$

(d) $2$

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