Question

$[2\sqrt{54}-6\sqrt{\frac{2}{3}}-\sqrt{96}]$ is equal to

• A. $0$
• B. $1$
• C. $2$
• D. $\sqrt{6}$

Answer 1

The correct option is A $0$

Expression = $2\sqrt{5}4-6\sqrt{\frac{2}{3}}-\sqrt{96}$

$=2\sqrt{9\times 6}-\sqrt{\frac{2\times 6\times 6}{3}}-\sqrt{16\times 6}$

$=2\times 3\sqrt{6}-2\sqrt{6}-4\sqrt{6}=0$.