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Byju's Answer
Standard IX
Mathematics
Linear Equation in 2 Variables
2 tables and ...
Question
2
tables and
3
chairs cost Rs.
2000
.Where as
3
tables and
2
chairs cost Rs.
2500
.Find the total cost of
1
table and
5
chairs.
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Solution
Let the cost of a table be Rs.
x
and that of a chair be Rs.
y
.Then
2
x
+
3
y
=
2000
........
(
1
)
3
x
+
2
y
=
2500
........
(
2
)
Multiplying equation
(
1
)
by
3
and
(
2
)
by
1
, we get
6
x
+
9
y
=
6000
.........
(
3
)
6
x
+
4
y
=
5000
.........
(
4
)
Subtracting
(
4
)
from
(
3
)
we get
6
x
+
4
y
−
6
x
−
9
y
=
5000
−
6000
⇒
−
5
y
=
−
1000
⇒
y
=
−
1000
−
5
=
200
∴
y
=
200
Put
y
=
200
in
(
3
)
we get
2
x
+
3
×
200
=
2000
⇒
2
x
=
2000
−
600
=
1400
⇒
x
=
1400
2
=
700
So,Cost of a table
=
Rs.
700
and cost of a chair
=
Rs.
200
Hence cost of
1
table and
5
chairs
=
1
×
700
+
5
×
200
=
700
+
1000
=
Rs.
1700
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2
Similar questions
Q.
2
tables and
3
chairs together cost Rs.
2000
whereas
3
tables and
2
chairs together cost Rs.
2500
. Find the total cost of
1
table and
5
chairs.
Q.
Three chairs and two tables cost Rs.
700
and five chairs and three tables cost Rs.
1100
. What is the total cost of
2
chairs and
3
tables?
Q.
The cost of
2
chairs and
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tables is Rs.
800
and the cost of
4
chairs and
3
tables is Rs.
1000
. Find the cost of
2
chairs and
2
tables.
Q.
4
chairs and
3
tables cost
R
s
.2100
and
5
chairs and
2
tables cost
R
s
.1750
. Find the cost of
1
chair and
1
table separately.
Q.
4
tables and
3
chairs together cost Rs.
2250
and
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tables and
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chairs cost Rs.
1950
. Find the cost of
2
chairs and
1
table.
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