The correct option is B Rs.1700.00
Let the cost of a table be ₹x and that of a chair be \(₹ y\). Then, 2x+3y=2000
and, 3x+2y=2500
This system of equations may be written as
2x+3y−2000=0
3x+2y−2500=0
By using cross-multiplication, we get
x3x−2500−2×−200=−y2×−2500−3×−2000=12×2−3×3
⇒x−7500+4000=y−1000=1−5
⇒x=−3500−5=700 and y=−1000−5=200
∴ Cost of a table =₹700 and, cost of a chair ₹=200
Hence, cost of one table and 5 chairs =₹(x+5y)=₹1700.