2g of aluminium is treated separately with H2O at high temperature and excess of NaOH. The ratio of the volumes of hydrogen evolved is x:y. Find the value of xy.
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Solution
2Al+3H2OΔ−→Al2O3+3H22Al+2NaOH+2H2OΔ−→2NaAlO2+3H2
The ratio of volumes of hydrogen evolved is 1:1
Hence, 11=1