The correct option is A 9.33 atm
Given:
n=2 mol, V=5 L
T=273+27=300 K
a=4.17 atm L2 mol−2,b=0.0371 L mol−1.
R=0.082 atm L mol−1 K−1
Applying van der Waals equation for n moles
(P+an2V2)(V−nb)=nRT
⇒(P+4.17×2252)(5−2×0.0371)=2×0.082×300P=2×0.082×3004.92−0.667
on solving we get :
P=9.33 atm