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Question

2 moles of gas A effuses from a container in 10 min. How many moles of gas B would effuse through the same container in same time under similar conditions. Ratio of specific gas constant for gas A to the gas B is 1:16.

A
2
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B
1
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C
4
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D
8
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Solution

The correct option is D 8
We know,
Specific gas constant, Rspecific=RM
where M is molar mass.
Rspecific (A)Rspecific (B)=MBMA=116
From Graham's law of effusion,
rArB=MBMA
where rA and rB are the rate of effusion for gas A and B.
rArB=116=14
Also
VAtVBt=rArB=14
Where
VA and VB are the volume of gas effused and t is the time taken for effusion.
We know,
For same pressure and temperature,
Vn (no. of moles)
nAnB=rArB=14
nB=4nA=4×2=8 moles

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