2.The sum of first p,q,r terms of an AP are a,b,c respectively. Then show that a(q-r)/p +b(r-p)/q + c(p-q)/r =0

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\frac{a (q - r)}{p} + \frac{b (r - p)}{q} + \frac{c (p - q)}{r} = 0

If $p^{t h}$ , $q^{t h}$ and $r^{t h}$ terms of an A.P. are a, b, c respectively, then show that: $a (q - r) + b (r - p) + c (p - q) = 0$

p^{t h}

q^{t h}

r^{t h}

a, b, c

a (q - r) + b (r - p) + c (p - q) = 0

p^{t h}, q^{t h}

r^{t h}

A . P

a, b, c

a (q - r) + b (r - p) + c (p - q) = 0

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