2- 10-3 moles of an acid containing An- ion uses up 1-2- 10-3 moles of MnO4- for the oxidation of An- to AO3- - The value of n is-

The correct option is C 2 2 ×10^ 3 moles of acid #160;corresponds to 1.2 ×10^ 3 moles MnO_4^ .Equating the equivalents of acid and per ...

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Redox Reactions

2× 10-3 moles...

Question

$2 \times 10^{- 3}$ moles of an acid containing $A^{n +}$ ion uses up $1.2 \times 10^{- 3}$ moles of $M n O_{4}^{-}$ for the oxidation of $A^{n +}$ to $A O_{3}^{-}$ . The value of $n$ is:

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Solution

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Similar questions

2.68 \times 10^{- 3}

A^{n +}

1.61 \times 10^{- 3}

M n O_{4}^{-}

A^{n +}

A O_{3}^{-}

n

2.68 \times 10^{- 3}

A^{n +}

1.61 \times 10^{- 3}

M n O_{4}^{-}

A^{n +}

A O_{3}^{-}

2.68 \times 10^{- 3}

A^{n +}

1.61 \times 10^{- 3}

M n O_{4}^{-}

A^{n +}

A O_{3}^{-}

2.68 \times 10^{- 3} mol

A^{n +}

1.61 \times 10^{- 3} mol

M n O_{4}^{-}

A^{n +}

A O_{3}^{-}

n

2.68 \times 10^{- 3} m o l

A^{n +}

1.6 \times 10^{- 3}

{M n O_{4}}^{- 1}

A^{n +}

{A O_{3}}^{- 1}

n

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