2 - 103 -2 - 106 -2 - 1012-

The correct option is A 8× 10^21a^x× a^y× a^z =a^x+y+z So, nbsp; (2× 10^3) × nbsp;(2× 10^6) nbsp;× (2× 10^12) = 2 × 2× 2× 10^(3+6+12) =8× 10^21 ...

399

You visited us 399 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Exponents with Like Bases

2 × 103 ×2 × ...

Question

$(2 \times 10^{3}) \times (2 \times 10^{6}) \times (2 \times 10^{12}) =$ _________.

8 \times 10^{21}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6 \times 10^{21}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 \times 10^{9}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 \times 10^{42}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $8 \times 10^{21}$
$a^{x} \times a^{y} \times a^{z} = a^{x + y + z}$

So,
$(2 \times 10^{3}) \times (2 \times 10^{6}) \times (2 \times 10^{12}) = 2 \times 2 \times 2 \times 10^{(3 + 6 + 12)} = 8 \times 10^{21}$

Suggest Corrections

Similar questions

Express the following standard form.

(a) 5 × 10⁶ + 4 × 10⁵ + 2 × 10³ + 9 × 10² + 6 × 10⁰

(b) 4 × 10⁵ + 8 ×10³ + 7 × 10¹

Write the numeral whose expanded form is given below:
(i) $6 \times 10^{4} + 3 \times 10^{3} + 0 \times 10^{2} + 7 \times 10^{1} + 8 \times 10^{0}$
(ii) $9 \times 10^{6} + 7 \times 10^{5} + 0 \times 10^{4} + 3 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 2 \times 10^{0}$
(iii) $8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 2 \times 10^{2} + 9 \times 10^{1} + 6 \times 10^{0}$

Q. Order of magnitude of

(10^{6}

10^{3})

Q. The usual form of

2 \cdot 73 \times 10^{12}

is:

103^{2} =

Join BYJU'S Learning Program

(2×103)×(2×106)×(2×1012)= _________.

The correct option is A 8×1021ax×ay×az=ax+y+z So, (2×103)×(2×106)×(2×1012)=2×2×2×10(3+6+12)=8×1021

$(2 \times 10^{3}) \times (2 \times 10^{6}) \times (2 \times 10^{12}) =$ _________.

The correct option is A $8 \times 10^{21}$
$a^{x} \times a^{y} \times a^{z} = a^{x + y + z}$

So,
$(2 \times 10^{3}) \times (2 \times 10^{6}) \times (2 \times 10^{12}) = 2 \times 2 \times 2 \times 10^{(3 + 6 + 12)} = 8 \times 10^{21}$