-2 -2 imes 2 times -2 -16

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Byju's Answer

Standard VII

Mathematics

Properties of Multiplication of Integers

-2 -2 imes 2 ...

Question

$(- 2) \times (- 2) \times 2 \times - 2 = - 16$

True

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False

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Solution

The correct option is A
True

The product of three negative numbers has a negative sign.

So, $(- 2) \times (- 2) \times 2 \times - 2 = - 16$

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Similar questions

Q. Why this series occurs in square numbers.

0 \times 0 = 0, 1 \times 1 = 1 d i f f e r e n c e = 1 1 \times 1 = 1, 2 \times 2 = 4 d i f f e r e n c e = 3 2 \times 2 = 4, 3 \times 3 = 9 d i f f e r e n c e = 5 3 \times 3 = 9, 4 \times 4 = 16 d i f f e r e n c e = 7 4 \times 4 = 16, 5 \times 5 = 25 d i f f e r e n c e = 9 5 \times 5 = 25, 6 \times 6 = 36 d i f f e r e n c e = 11 6 \times 6 = 36, 7 \times 7 = 49 d i f f e r e n c e = 13 7 \times 7 = 49, 8 \times 8 = 64 d i f f e r e n c e = 15

8 \times (3 + 2 \times 2) = ?

Question 5

Study the pattern:
$\begin{matrix} 1 \times 8 + 1 = 9; & 12 \times 8 + 2 = 98; & 123 \times 8 + 3 = 987 1234 \times 8 + 4 = 9876; & 12345 \times 8 + 5 = 98765 \end{matrix}$

Write the next two steps. Can you say how the pattern works?

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(i) \frac{6.25 \times 6.25 - 1.75 \times 1.75}{4.5} (i i) \frac{198 \times 198 - 102 \times 102}{96}

Choose the correct answers from the given options .

Question 10

Which of the following is equal to 1?
$(a) 2^{0} + 3^{0} + 4^{0} (b) 2^{0} \times 3^{0} \times 4^{0} (c) (3^{0} - 2^{0}) \times 4^{0} (d) (3^{0} - 2^{0}) \times (3^{0} + 2^{0})$

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(−2)×(−2)×2×−2 =−16

The correct option is A True The product of three negative numbers has a negative sign. So, (−2)×(−2)×2×−2 =−16

$(- 2) \times (- 2) \times 2 \times - 2 = - 16$

The correct option is A
True

The product of three negative numbers has a negative sign.

So, $(- 2) \times (- 2) \times 2 \times - 2 = - 16$