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Question

2% (w/w) HCl stock solution has a density of 1.25g mL1. The molecular weight of HCl is 36.5g mol1. The volume (mL) of stock solution required to prepare 200 mL solution of 0.4 M HCl is _____.

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Solution

2% (w/w) HCl solution means 2 gm of HCl present in 100 gm of solution.

Moles of HCl =236.5

Density = 1.25 gmL1

Volume of solution =MassDensity

=1001.25

=80 mL

Molarity of stock solution of HCl,

=Moles×1000V(mL)

=2×100036.5×80=0.684 M

The volume of stock solution required to prepare 200 mL of 0.4 M HCl is,

V1=M2V2V1

=0.4×2000.684=116.9 mL

Hence, the correct answer is 116.9 mL.

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