2% (w/w) HCl stock solution has a density of 1.25gmL−1. The molecular weight of HCl is 36.5gmol−1. The volume (mL) of stock solution required to prepare 200 mL solution of 0.4 M HCl is _____.
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Solution
2% (w/w) HCl solution means 2 gm of HCl present in 100 gm of solution.
Moles of HCl =236.5
Density = 1.25 gmL−1
∴ Volume of solution =MassDensity
=1001.25
=80mL
Molarity of stock solution of HCl,
=Moles×1000V(mL)
=2×100036.5×80=0.684M
The volume of stock solution required to prepare 200mL of 0.4M HCl is,