The correct option is
A Time taken by 1 woman alone to finish the work: 18 days, and also that taken by 1 man alone: 36 daysLet the work done by man and woman per day be x and y respectively.
When the work is completed in 4 days
Since 5 men and 2 women complete the work in 4 days
therefore work done by
5 men and
2 women in
1 day
= 14∴5x+2y=14⟶eqn1
When the work is completed in 3 days
Since 6 men and 3 women complete the work in 3 days
therefore work done by 6 men and 3 women in 1 day = 13
∴6x+3y=13⟶eqn2
Multiplying by 3 in eqn1, we get
⇒15x+6y=34⟶eqn3
Multiplying by 2 in eqn2, we get
⇒12x+6y=23⟶eqn4
On subtracting eqn 4 from eqn 3, we get
⇒15x+6y−12x−6y=34−23
⇒3x=112
⇒x=136
On substituting the value of x in eqn2, we get
⇒6×136+3y=13
⇒3y=13−16
⇒y=118
Thus,
work done by 1 man in 1 day =136 days
∴ Time taken by 1 man alone to finish the work =36 days
work done by 1 woman in 1 day =118 days
∴ Time taken by 1 woman alone to finish the work =18 days