2 women and 5 men did a work in 4 days while 3 women and 6 men finished it in 3 days ,find the time taken by 1 woman alone and 1 man alone to do the work?

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Solution

Let the work done by woman be x & man be y. Total work be W
4(2x+5y)=W
2x+5y= $\frac{W}{4}$ ...(1)
3x+6y= $\frac{W}{3}$ ...(2)
(2)-(1)
x+y= $\frac{W}{12}$
W=12(x+y)
Number of days if a man & woman work, they will together take 12 days.

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2 women and 5 men did a work in 4 days while 3 women and 6 men finished it in 3 days ,find the time taken by 1 woman alone and 1 man alone to do the work?

Let the work done by woman be x & man be y. Total work be W 4(2x+5y)=W 2x+5y=W4 ...(1) 3x+6y=W3 ...(2) (2)-(1) x+y=W12 W=12(x+y) Number of days if a man & woman work, they will together take 12 days.

Let the work done by woman be x & man be y. Total work be W
4(2x+5y)=W
2x+5y= $\frac{W}{4}$ ...(1)
3x+6y= $\frac{W}{3}$ ...(2)
(2)-(1)
x+y= $\frac{W}{12}$
W=12(x+y)
Number of days if a man & woman work, they will together take 12 days.