Question 19.2
Write the balanced chemical equation for the following reaction and identify the type of reaction:

Sodium hydroxide solution is treated with acetic acid to form sodium acetate and water.

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Solution

$NaOH (aq) + {CH}_{3} COOH (aq) \to {CH}_{3} COONa (aq) + H_{2} O(l)$

It is a neutralisation reaction as an acid is reacting with a base to form salt and water.

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Write the type of reaction :

Sodium hydroxide solution is treated with acetic acid to form sodium acetate and water.

Question 33
Write a balanced chemical equation for each of the following reactions and also classify them.

(a) Lead acetate solution is treated with dilute hydrochloric acid to form lead chloride and acetic acid solution.

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(d) Hydrogen sulphide gas reacts with oxygen gas to form solid sulphur and liquid water.

Question 19.3

Write the balanced chemical equation for the following reaction and identify the type of reaction.

Ethanol is warmed with ethanoic acid to form ethyl acetate in the presence of concentrated $H_{2} {SO}_{4}$ .

Write a balanced chemical equation with state symbols for the following reactions.

(i) Solutions of barium chloride and sodium sulphate in water react to give insoluble barium sulphate and the solution of sodium chloride.

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Q. Write the chemical equation for the following reactions: (a) Calcium hydroxide reacts with nitric acid. (b) Acetic acid reacts with calcium. (c) Hydroxide acid reacts with sodium hydroxide. (d) Ammonium hydroxide reacts with sulphuric acid

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Question 19.2 Write the balanced chemical equation for the following reaction and identify the type of reaction: Sodium hydroxide solution is treated with acetic acid to form sodium acetate and water.

NaOH(aq)+CH3COOH (aq)→CH3COONa (aq)+H2O(l) It is a neutralisation reaction as an acid is reacting with a base to form salt and water.

Question 19.2
Write the balanced chemical equation for the following reaction and identify the type of reaction:

Sodium hydroxide solution is treated with acetic acid to form sodium acetate and water.

$NaOH (aq) + {CH}_{3} COOH (aq) \to {CH}_{3} COONa (aq) + H_{2} O(l)$

It is a neutralisation reaction as an acid is reacting with a base to form salt and water.