Question

$2x^2-9x+10=0$, when $\left(ii\right)x\in Q,\left(i\right)x\in N$

Answer 1

$2x^2-9x+10=0$

$2x^2$-$5x$-$4x$+$10=0$

$x(2x-5)-2(2x-5)=0$

$(x-2)(2x-5)=0$

$x=2$,$x=\frac{5}{2}$

$x=2$, $xϵN$

$x=\frac{5}{2}$ $xϵ$$Q$