Question

2·x=acos θ, y = b cose

Answer 1

It is given that x and y are parametrically connected by the equations,

x=acosθ(1)

And,

y=bcosθ(2)

Differentiate equation (2) with respect to θ.

dy dθ =b( −sinθ ) dy dθ =−bsinθ

Differentiate equation (1) with respect to θ.

dx dθ =a( −sinθ ) dx dθ =−asinθ

We know that,

dy dx = dy dθ dx dθ

Substitute the value of dy dθ and dx dθ .

dy dx = −bsinθ −asinθ dy dx = b a

Thus, the solution is dy dx = b a .