20. Account for the following . (a) CaCl2 is used to clear snow from roads to hill stations . (b) ethylene glycol is used as antifreeze solution in ratiators of vehicles in cold countries . (c) the freezing point depression of 0.01 m NaCl is nearly twice that of 0.01 m glucose solution

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Q. In a cold climate, water gets frozen causing damage to the radiators of a car. Ethylene glycol is used as an antifreeze agent. The mass of ethylene glycol to be added to 4 kg water to prevent it from freezing at

- 6^{o} C . K_{f}

for water is

1.85 K m o l^{- 1} k g

Question 11
In comparison to a 0.01 M solution of glucose, the depression in freezing point of a $0.01 M M g C l_{2}$ solution is ........... .
(a) the same (b) about twice
(c) about three times (d) about six times

Q. Why the freezing point depression

(Δ T_{f})

0.4 M

N a C l

solution is nearly twice than that of

0.4 M

glucose solution?

Q. In cold climate, water freezes causing damage to the radiator of the car . Ethylene glycol is used as an antifreeze. The amount of ethylene glycol to be added to 4 kg of water to prevent it from freezing at

- 6^{o} C

(

K_{f}

of water =

1.85 K m^{- 1}

)

Q. Let’s think that you are driving in a car in winter. In a cold climate water gets frozen causing damage to radiator of a car. Ethylene glycol is used as an antifreezing agent. Calculate the amount of ethylene glycol to be added to 4 kg of water to prevent it from freezing at

- 6^{\circ} C

(K_{f}

for water =

1.85 K k g m o l^{- 1})

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