Question

$20$ Books are to be distributed between four friends $A,B,C$ and $D$ such that they receive $3,4,5$ and $8$ number of books respectively. The number of ways that this distribution can be done is

• A. $\frac{20!}{3!4!5!}$
• B. $\frac{12!}{3!4!5!}$
• C. $\frac{20!}{3!4!5!8!}$
• D. $\frac{12!}{3!4!5!8!}$

Answer 1

Answer: (C)

$\frac{20!}{3!4!5!8!}$

Assuming all the books are of different type.
Required number of ways $=\frac{20!}{3!.4!.5!.8!}$