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Concentration Terms - An Introduction (w/w etc)

20 cm 3 of an...

Question

20 $c m^{3}$ of an alcohol is dissolved in 80 $c m^{3}$ of water. Calculate the percentage by volume of alcohol in solution

10 %

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15 %

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30 %

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20 %

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Solution

The correct option is D 20 %
Given: Volume of alcohol = 20 $c m^{3}$
Volume of water = 80 $c m^{3}$
$% v / v$ of alcohol = $\frac{volume of the component (mL)}{volume of the solution (mL)} \times 100$
$% v / v = \frac{20}{20 + 80} \times 100 = 20$ %

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Concentration Terms - An Introduction (w/w etc)

Standard XII Chemistry

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20 cm3 of an alcohol is dissolved in 80 cm3 of water. Calculate the percentage by volume of alcohol in solution

The correct option is D 20 %Given: Volume of alcohol = 20 cm3 Volume of water = 80 cm3 % v/v of alcohol = volume of the component (mL)volume of the solution (mL)×100 % v/v=2020+80×100=20 %

20 $c m^{3}$ of an alcohol is dissolved in 80 $c m^{3}$ of water. Calculate the percentage by volume of alcohol in solution

The correct option is D 20 %
Given: Volume of alcohol = 20 $c m^{3}$
Volume of water = 80 $c m^{3}$
$% v / v$ of alcohol = $\frac{volume of the component (mL)}{volume of the solution (mL)} \times 100$
$% v / v = \frac{20}{20 + 80} \times 100 = 20$ %