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Question

20) Determine the molecular formula of an oxide of iron, in which the mass per cent of iron and
oxygen are 69.9 and 30.1, respectively.

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Solution

Dear StudentMass percent of iron and oxygen are 69.1% and 30.1% respectively.Mass of iron=69.1 gMass of oxygen=30.1 gMole of iron=69.156=1.23Mole of oxygen=30.116=1.88Mole ratio is-Fe:O=1.23:1.88=1.231.23:1.881.23=1:1.5=2:3So, the formula of iron oxide is Fe2O3.Regards

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