Question

$20d{m}^3$ of $S{O}_2$ diffuse through a porq partition in $60s$. What volume of $O_2$ will diffuse under similar conditions in $30s$.

Answer 1

Rate of diffusion of $S{O}_2=\frac{20}{60}d{m}^3{s}^{-1}$
Rate of diffusion of $O_2=\frac{V}{30}d{m}^3{s}^{-1}$
According to Graham's law of diffusion,
$\frac{\left(V/30\right)}{\left(20/60\right)}=\sqrt{\frac{M_{S{O}_2}}{M_{O_2}}}=\sqrt{\frac{64}{32}}$
$V=14.1d{m}^3$.