The correct option is A 0.86
Weight of solute(w)=0.25 g Weight of solvent(W)=20 g=201000 kgΔTf=0.3∘C=0.3 K
Let mobs be observed molecular mass of solute
mobs=Kf×wW×ΔTmobs=5.12×0.25×100020×0.3=213.3 g mol−1
Theoretical molecular mass of solute =122 g mol−1
So, i=Theoretical molecular massObserved molecular mass=122213.3=0.57
Degree of association (β) :
β=(i−1)×n(1−n)
Since solute dimerises, so n=2
Putting the values:
β=(0.57−1)×2(1−2)β=0.86