Question

20. If from 3 moles $MgS{O}_{4}7H_{2}O$, all the 'O' atoms are taken out and converted into ozone find the number of O₃ molecules formed.

Answer 1

The solution is as follows:

Number of atoms of O in one molecule of MgSO₄.7H₂O = 4+7 = 11

3 moles of ​MgSO₄.7H₂O has 3$\times$11$\times$6.023$\times$10²³ atoms of O.

1 molecule of ozone needs 3 O atoms.

Thus, number of molecules of ozone formed = $\frac{3\times 11\times 6.023\times {10}^{23}}{3}=11\times 6.023\times {10}^{23}$ molecules of Ozone.