Question

20 $l$ of $S{O}_2$ diffuses through a porous partition in 6.0 seconds. Volume of $O_2$ diffused under similar conditions in 30 seconds will be :

• A. 121.14 $l$
• B. 141.4 $l$
• C. 182.14 $l$
• D. 28.14 $l$

Answer 1

The correct option is B 141.4 $l$

Diffusion Rate $r=\frac{V}{t}$

$r_{S{O}_2}=\frac{20}{6}$

$r_{O_2}=\frac{V}{30}$

According to Graham's Law $\frac{r_{O_2}}{r_{S{O}_2}}=\sqrt{\frac{M_{S{O}_2}}{M_{O_2}}}$

$\frac{0.033V}{3.3}=\sqrt{\frac{64}{32}}=1.414\Rightarrow V=\frac{1.414}{0.01}=141.4l$