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20 ml N10 ...

Question

20 ml $\frac{N}{10}$ $H C l$ is mixed with 40 ml $\frac{N}{10}$ NaOH solution. The normality of the resultant acidic/basic solution will be:

\frac{N}{20}

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\frac{N}{30}

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\frac{N}{40}

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\frac{N}{15}

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Solution

The correct option is B $\frac{N}{30}$
Normality of Resultant Sol = $\frac{N_{2} V_{2} - N_{1} V_{1}}{V_{1} + V_{2}}$

Normality = $\frac{[4 - 2] N}{60}$

Normality = $\frac{N}{30}$

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20 ml N10 HCl is mixed with 40 ml N10 NaOH solution. The normality of the resultant acidic/basic solution will be:

The correct option is B N30Normality of Resultant Sol = N2V2−N1V1V1+V2Normality = [4−2]N60Normality = N30

20 ml $\frac{N}{10}$ $H C l$ is mixed with 40 ml $\frac{N}{10}$ NaOH solution. The normality of the resultant acidic/basic solution will be:

The correct option is B $\frac{N}{30}$
Normality of Resultant Sol = $\frac{N_{2} V_{2} - N_{1} V_{1}}{V_{1} + V_{2}}$

Normality = $\frac{[4 - 2] N}{60}$

Normality = $\frac{N}{30}$