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Question

20 mL of 0.1 M H2SO4 solution is added to 30 mL of 0.2 M NH4OH solution. The pH of the resultant mixture is [pKb of NH4OH=4.7, log2=0.3010]

A
5.2
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B
9
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C
5
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D
9.4
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Solution

The correct option is B 9
Millimoles of H2SO4=20×0.1=2
Millimoles of NH4OH=30×0.2=6

H2SO4+2NH4OH(NH4)2SO4+2H2O
Initial 2 6 0
Equilibrium 0 64=2 2

Total volume=30+20=50 mL
[(NH4)2SO4]=250 M [NH+4]=250×2=450 M[NH4OH]=250 M

pOH=pKb+log[NH+4][NH4OH] =4.7+log450250pOH=4.7+log25.0 pH=14pOHpH=145=9.0

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