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Question

20 mL of 0.1 M H2SO4 solution is added to 30 mL of 0.2 M NH4OH solution. The pH of the resultant mixture is:
[Pkb of NH4OH= 4.11]

A
9.4
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B
5
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C
9
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D
5.2
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Solution

The correct option is C 9
Moles equivalent of H2SO4= 20 × 0.1 = 2
Moles equivalent of NH4OH= 30 × 0.2 = 6

NH4OH+H+NH4+ +H2O6 4 0 02 0 4 4Solution is basic bufferpOH=pkb+logNH4+NH4OH =4.7+log 42 =4.7+log2 =4.7+0.3=5 14=pOH+pH pH=145=9

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