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Question

20 mL of 0.1 M weak acid HA (Ka=105) is mixed with the solution of 10 mL of 0.3 M HCl and 10 mL of 0.1 M NaOH. Find the value of [A]([HA]+[A]) in the resulting solution?

A
2×104
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B
2×105
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C
2×103
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D
0.05
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Solution

The correct option is A 2×104
As we know,
Cα=[A]=[H+]=Ka×C=103 M.
So, 20 mL of solution will have [A]=20×103×103.
Since [HA]>>>[A], [A][HA]+[A]=[A][HA]=2×1050.1=2×104.

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