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Volume of Gases and Number of Moles

20 mL of 0....

Question

$20$ mL of $0.1 M$ solution of compound $N a_{2} C O_{3} . N a H C O_{3} .2 H_{2} O$ is titrated against $0.05 M H C l, x m L$ of $H C l$ is used when phenolphthalein is used as an indicator and $y m L$ of $H C l$ is used when methyl orange is the indicator in two separate titrations. Hence $(y - x)$ is: (in ml)

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Solution

When phenolphthalein is used as an indicator;
$0.05 x = 20 \times 0.1 \times 1; x = 40 m L$ (Here only one part reacts)
When methyl orange is used as an indicator;
$0.05 y = 20 \times 0.1 \times 3$ (Here, all three part of base reacts)
$y = 120 m L$ .
$∴ y - x = 80 m L$ .

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20

0.1 M

solution of compound

N a_{2} C O_{3} . N a H C O_{3} .2 H_{2} O

, is titrated against

0.05 M H C l . x

H C l

is used when phenolphthalein is used as an indicator and

y

H C l

is used when methyl orange is the indicator in two separate titrations. Hence,

(y - x)

40

0.05 M

solution of sesqui-carbonate

(N a_{2} C O_{3} . N a H C O_{3} .2 H_{2} O)

is titrated against

0.05 M

H C l

x

H C l

is used when phenolphthalein is the indicator and

y

H C l

is used when methyl orange is the indicator in two separate titrations. Hence,

(y - x)

40 m L

0.05 M N a_{2} C O_{3} \cdot N a H C O_{3} \cdot 2 H_{2} O

(sesquicarbonate) is titrated against

0.05 M H C l . x m L

H C l

is used when phenolphthalein is the indicator and

y m L H C l

is used when methyl orange is the indicator in two separate titrations, hence

(y - x)

Q. Given two mixtures: (A)

N a O H

N a_{2} C O_{3}

(B)

N a H C O_{3}

N a_{2} C O_{3}

.

100

mL of mixture (A) required

a

b

1 M

H C l

in separate titration using phenolphthalein and methyl orange indicators respectively while

100

mL of mixture (B) required

x

y

H C l

solution is separate titration using the same indicators.

Q. A 20 ml solution of 0.1 N

N a_{2} C O_{3}

is titrated with 0.1N HCl with phenolphthalein as the indicator. Another 20 ml solution of 0.1 N

N a_{2} C O_{3}

is titrated with 0.1 N HCl with methyl orange as the indicator. The volume of HCl required for both the titrations resepectively is:

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