Question

20 ml of 0.2 M${AI}_2{\left({SO}_4\right)}_3$ is mixed 20 ml of 6.6 M $Ba{CI}_2$. the concentration of ${CI}^{-}$ ion in solution is ?

• A. 0.2 M
• B. 6.6 M
• C. 0.02 M
• D. 0.06 M

Answer 1

The correct option is B 6.6 M

Concentration of $C{l}^{-}=\frac{Moles-of-C{l}^{-}}{Total-volume}$

Given,

Total moles of $C{l}^{-}=20\times 6.66\times 20\times {10}^{-3}=2.664moles$

Total volume=$20\times {10}^{-3}+20\times {10}^{-3}=40\times {10}^{-3}ml$

Therefore, Concentration of $C{l}^{-}=\frac{2.664}{40\times {10}^{-3}}=6.6M$